For every 1°C of temperature increase in the atmosphere, on the Planet
the heat increases by 0.34%.
Author; Rogelio Pérez C
Summary;
In the climate change problem, knowing how much heat on the planet increases for every degree centigrade that the temperature increases in the atmosphere is the main key to understanding the problem known as global warming, for we would know precisely what is the true critical point or "point of no return" that could be catastrophic for the planet. The theory of the greenhouse effect, which is one of the sciences that teaches how the temperature increases on the planet, explains that the increase of certain gases in the atmosphere known as greenhouse gases is the cause of the temperature and the atmospheric heat, according to this, we live almost on the brink of a climate catastrophe due to the increase in these gases.The greenhouse effect theory uses a concept called equilibrium climate sensitivity to explain the temperature changes caused by this effect. And it consists of a hypothetical value given in degrees Celsius to validate its hypothesis, but hypothetical values are assumptions.But the kinetic theory of gases, which is the other theory with which we can explain the temperature and atmospheric heat, shows us mathematically, as soon as the heat on the planet increases, when the temperature rises 1 degree Celsius. Although the concepts of heat and temperature are related to each other, they have different characteristics, because while temperature is the measure of the kinetic movement of atoms or molecules within a system, and it is given in degrees Celsius, heat is the transfer of this energy between atoms or molecules of different systems, and it is given in Joules. With this work I show that the increase in the heat level in the gas molecules that make up the atmosphere is 12.46 joules or 0.34% of the heat, when the temperature of the molecules increases by a degree centigrade.
Introduction
The world is currently implementing many strategies to address the global climate problem, based on the science of greenhouse effect theory, and the best solution today is the reduction of certain gases in the atmosphere, called greenhouse gases, such as CO2,The greenhouse effect theory uses a concept called equilibrium climate sensitivity to explain the temperature changes caused by this effect. And it consists of a hypothetical value given in degrees Celsius to validate its hypothesis, but hypothetical values are assumptions.This work is written to show a new way of understanding the climate on the planet, based on the kinetic theory of gases, so that we can better understand the problem of heat on the planet. According to the greenhouse effect theory, infrared radiation and the gases that absorb this energy are the cause of the increase in atmospheric heat, but according to this research the absorption of infrared radiation by greenhouse gases, it cannot be the cause of the temperature increase in the atmospheric system, because 99.9% of the molecules in this system do not absorb infrared, although all molecules in this atmospheric system emit infrared, which allows to measure their temperature, Since infrared emitted by the earth's surface, which are absorbed and retained by greenhouse gases in the atmospheric system, is the cause of the infrared emitted by the atmosphere, this would nullify the capacity of the gas molecules that make up the atmospheric system to cause its own temperature.
Science teaches that the temperature of any system is given by the
measurement of the kinetic energies of the atoms or molecules that compose it,
but heat is the kinetic energy that can be transferred by the atoms or
molecules of a system, to the atoms or molecules of other systems with less
kinetic energy, this work measures the differences in the kinetic energies of
the main gas molecules that make up the atmosphere, when they are at 14°C and
15°C, to know the difference in heat, which gas molecules in the atmosphere can
transfer to other systems, when their temperature increases by 1 degree
Celsius.
Theory statement and
definitions
The greenhouse
effect theory
The greenhouse
effect is a process in which thermal radiation emitted by the planetary surface
is absorbed by atmospheric greenhouse gases (GHGs) and radiated in all
directions. As part of this radiation is returned to the Earth's surface and
lower atmosphere.1
How is the temperature in the greenhouse effect theory explained?
This uses a concept called climate sensitivity, which is a measure of how the temperature of the climate system responds to a change in the radiative forcing (the difference between the solar light absorbed by Earth and the energy radiated back into space). This shows as the temperature change associated with a doubling of the concentration of carbon dioxide in the atmosphere. 1.1
How is temperature measured based on greenhouse effect theory?
This measures temperature based on the equilibrium climate sensitivity range.
What is the equilibrium climate sensitivity range?
(ECS, is a
hypothetical value (assumption or some possible or impossible theory to draw
any particular consequence, cause, or reason) of equilibrium global warming to
double CO2. And because it is a hypothetical value it may change according to
the researcher, but the greatest value used in the models generated in the
1990s, is the hypothetical value of 1.8°C to 5.6°C.1.2
Kinetic of
gases theory
The kinetic of
gases theory is a physical and chemical theory that explains the macroscopic
behavior and properties of gases (the law of ideal gases), based on a
statistical description of microscopic molecular processes. The kinetic theory
was developed based on studies by physicists such as Daniel Bernoulli in the
18th century, Ludwig Boltzmann and James Clerk Maxwell in the late 19th
century.2
Charles law for
gases, for any gas, the ratio between temperature and
volume is directly proportional, if the quantity of gas and pressure remain
constant.
Mathematically
we can express it like this:
Where;
V is the volume
T is the
absolute temperature (i.e measured in kelvin).
k is the
constant of proportionality.3
Heat, q, is
thermal energy transferred from a hotter system to a cooler system that are in
contact. Temperature is a measure of the average kinetic energy of the atoms or
molecules in the system. The zeroth law of thermodynamics says that no heat is
transferred between two objects in thermal equilibrium; therefore, they are the
same temperature.4
Heat, is
thermal energy transferred from a hotter system to a cooler system that are in
contact.
We can
calculate the heat released or absorbed using the specific heat capacity C, the
mass of the substance, m, and the change in temperature, ΔT in the equation: q=m×C×ΔT
Heat and
temperature are two different but closely related concepts. Note that they have
different units: temperature typically has units of degrees Celsius (degrees
°C,) or Kelvin (K), and heat has units of energy, Joules (J).
Temperature is
a measure of the average kinetic energy of the atoms or molecules in the
system. The water molecules in a cup of hot coffee have a higher average
kinetic energy than the water molecules in a cup of iced tea, which also means
they are moving at a higher velocity.5
Temperature is
also an intensive property, which means that the temperature doesn't change no
matter how much of a substance you have (as long as it is all at the same
temperature!). This is why chemists can use the melting point to help identify
a pure substance—minus the temperature at which it melts is a property of the
substance with no dependence on the mass of a sample.
The
equipartition theorem relates the temperature of a system to its average
energies. It makes quantitative predictions, provides the total kinetic and
potential energies for a system at a given temperature, from which the heat
capacity of the system can be calculated. However, the equipartition also
provides the average values of individual energy components, such as the
kinetic energy of a particular particle or the potential energy of a single
spring. For example, it predicts that each atom in an ideal monoatomic gas has
an average kinetic energy of (3/2) k B T in thermal equilibrium, where k B is
Boltzmann's constant and Te the temperature (thermodynamics).6
Thermal motion of an α-helical peptide. The
jittery motion is random and complex and the energy of any particular atom can
fluctuate wildly. Nevertheless, the equipartition theorem allows the average
kinetic energy of each atom to be computed, as well as the average potential
energies of many vibrational modes. The grey, red and blue spheres represent
atoms of carbon, oxygen and nitrogen, respectively; the smaller white spheres
represent atoms of hydrogen.7
The mole
(symbol: mole) is the unit with which the amount of substance is measured, one
of the seven fundamental physical magnitudes of the International System of
Units.
In any
substance (chemical element or compound) and considering at the same time a certain
type of elemental entities that make up it, the mole, mole symbol, is the SI
unit of quantity of substance. A mole contains exactly 6,022 140 76 × 10–23
elemental entities.8
Kinetic energy
is the energy of a moving body. Kinetic energy is defined as the work to be
done by the force it exerts on the resting body to accelerate it.9
Development
To begin, we
will find the quadratic mean velocity of each molecule of these 4 gases at a
temperature of 15°C; the formula is as follows;
Nitrogen 78%
R= 8.31 J/mol.k
T= 15+273=288 k
M (N2) =
14.0067 + 14.0067 =28 g/mol
=0.028kg/mol
Vcm= √ (3 *8,
31 *288)/0.028=
Vcm= √ (24.93
*288)/0.028=
Vcm= √7179.8 /
0.028=506.38 m/s
Oxygen 21%
R= 8.31 J/mol.k
T= 15+273=288 k
M (O2) = 16. + 16 =32 g/mol
=0.032kg/mol
Vcm= √ (3 *8.31
*288)/0.032=
Vcm= √ (24.93
*288)/0.032=
Vcm= √7179.8/
0.032= 473.67 m/s
Argon 0.934%
R= 8.31 J/mol.k
T= 15+273=288k
M (Ar) = 39.9
=39.9 g/mol
=0.0399kg/mol
Vcm= √ 3 *8, 31
*288/0.0399=
Vcm= √ (24.93 *288)/0.0399=
Vcm= √ 7179.8 /
0.0399= 424.2 m/s
Carbon dioxide
(CO2)
R= 8.31 J/mol.k
T= 15+273=288 k
M(CO2)= 12 +
2*16 =44 g/mol
=0.044kg/mol
Vcm= √3 *8, 31
*288/0.044=
Vcm= √ (24.93
*288)/0.044=
Vcm= √7179.8 /
0.044= 403, 95 m/s
|
Average
quadratic speed of the following molecules at 15°C temperature; |
|
|
GAS |
Vcm. Of molecules at 15°C |
|
Nitrogen (N2) |
506.38 m/s |
|
Oxygen (O2) |
473.67 m/s |
|
Argón (Ar) |
424.20 m/s |
|
Carbon
dioxide (CO2) |
403.95 m/s. |
As the
temperature of the atmosphere is a measure of the average kinetic energy of its
molecules, then we will find the kinetic energy for each of the 4 main
molecules.
Kinetic energy
is a form of energy, known as motion energy. The kinetic energy of an object is
the energy produced by its mass-dependant movements and speed of the same.
Kinetic energy is usually abbreviated by the letters "EC" or
"Ek". The word kinetics is of Greek origin “kinesis” meaning
“movement”.
Kinetic energy is represented by the following formula: EC=½ mv². Kinetic energy is measured in Joules (J), mass in kilograms (kg) and velocity in meters over seconds (m/s).4
Nitrogen:
M= 0.028kg/mol
V²= 506.38m/s²
Ec= ½ 0.028kg/ mol(*506.38m/s) ²
Ec=3589.89 J
The kinetic energy (E) of a body with mass m =
0.028 kilograms and velocity v = 506.38 m/s equals 3589.89 J
Oxygen
M= 0.032kg/mol
V²= 473.67m/s²
Ec= ½ 0.032kg/ mol*(473.67 m/s) ²
Ec= 3589.81 J
The kinetic energy (E) of a body with mass m =
0.032 kilograms and velocity v = 473.67 m/s equals 3589.81 J
Argón
M= 0.0399kg/mol
V²= 424.20m/s
Ec= ½ 0.0399kg/ mol*(424.20 m/s) ²
Ec=3589.92 J
The kinetic energy (E) of a body with mass m =
0.0399 kilograms and velocity v = 424.20 m/s equals 3589.92 J
Carbón Dioxide
M= 0.044kg/mol
V²= 403.95m/s
Ec= ½ 0.044kg/ mol*(403.95 m/s) ²
Ec= 3589.86 J
The kinetic energy (E) of a body with mass m =
0.044 kilograms and velocity v = 403.95 m/s equals 3589.86 J
Kinetic energy of each mole of the different gases
|
GAS |
kinetic energy (Heat) at 15°C |
|
Nitrogen (N2) |
3589.89 J |
|
Oxygen (O2) |
3589.81 J |
|
Argón (Ar) |
3589.92 J |
|
Carbón
Dioxide (CO2) |
3589.86 J. |
Parts per million (ppm) is the unit that is
frequently used to measure the volume that occupy small amounts of elements
(also called traces) within a mixture.
|
The
parts per million of the following gases in the atmosphere |
|
|
GAS |
parts
per million |
|
Nitrogen (N2) |
780.800 |
|
Oxygen (O2) |
209.450 |
|
Argón (Ar) |
9.340 |
|
Carbón
Dioxide (CO2) |
410 |
|
GAS |
VOLUME PPM |
Kinetic energy per Mole gas 15°C |
TOTAL(Ek) Mole Gas x Volume 15°C |
|
Nitrogen (N2) |
780.800 |
3589.89 J |
2.802.986.112 J |
|
Oxygen (O2) |
209.450 |
3589.81 J |
751.885.705
J |
|
Argón (Ar) |
9.340 |
3589.92 J |
33.529.853
J |
|
carbón Dioxide(CO2) |
410 |
3589.86 J. |
1.471.843
J |
|
TOTAL |
1.000.000 |
3589,87 j |
3.589.873.512 J |
Now we will find the quadratic mean velocity of
each molecule of these 4 gases at a temperature of 14°C;
Nitrogen 78%
R= 8.31 J/mol.k
T= 14+273=287 k
M (N2) =
14.0067 + 14.0067 =28 g/mol
=0.028kg/mol
Vcm= √ (3 *8,
31 *287)/0.028=
Vcm= √ (24.93
*287)/0.028=
Vcm= √7154.9 /
0.028=505.50 m/s
Oxygen 21%
R= 8.31 J/mol.k
T= 14+273=287 k
M (O2) = 16. + 16 =32 g/mol
=0.032kg/mol
Vcm= √ (3 *8.31
*287)/0.032=
Vcm= √ (24.93
*287)/0.032=
Vcm= √7154.9/
0.032= 472.85 m/s
Argon 0.934%
R= 8.31 J/mol.k
T= 14+273=287k
M (Ar) = 39.9
=39.9 g/mol
=0.0399kg/mol
Vcm= √ 3 *8, 31
*287/0.0399=
Vcm= √ (24.93
*287)/0.0399=
Vcm= √ 7154.9 /
0.0399= 423.46 m/s
Carbon dioxide (CO2)
R= 8.31 J/mol.k
T= 14+273=287 k
M (CO2) = 12 +
2*16 =44 g/mol
=0.044kg/mol
Vcm= √3 *8, 31
*287/0.044=
Vcm= √ (24.93
*287)/0.044=
Vcm= √7154.9 /
0.044= 403, 25 m/s
|
Average
quadratic speed of the following molecules at 14°C temperature; |
|
|
GAS |
Vcm. Of molecules at 14°C |
|
Nitrogen (N2) |
505.50 m/s |
|
Oxygen (O2) |
472.85 m/s |
|
Argón (Ar) |
423.46 m/s |
|
Carbon
dioxide (CO2) |
403.25 m/s. |
Kinetic
energy is the energy that a moving body has. Kinetic energy is defined as the
work that must be performed by the force it exerts on the resting body to
accelerate it:
Nitrogen:
M= 0.028kg/mol
V²= 505.50m/s²
Ec= ½ 0.028kg/ mol(*505.50m/s) ²
Ec=3577.42 J
The kinetic energy (E) of a body with mass m =
0.028 kilograms and velocity v = 505.50 m/s equals 3577.42 J
Oxygen
M= 0.032kg/mol
V²= 472.85m/s²
Ec= ½ 0.032kg/ mol*(472.85 m/s) ²
Ec= 3577.39 J
The kinetic energy (E) of a body with mass m =
0.032 kilograms and velocity v = 472.85 m/s equals 3577.39 J
Argón
M= 0.0399kg/mol
V²= 423.46m/s
Ec= ½ 0.0399kg/ mol*(423.46 m/s) ²
Ec=3589.92 J
The kinetic energy (E) of a body with mass m =
0.0399 kilograms and velocity v = 423.46 m/s equals 3577.4 J
Carbón Dioxide
M= 0.044kg/mol
V²= 403.25m/s
Ec= ½ 0.044kg/ mol*(403.25 m/s) ²
Ec= 3577.43 J
The kinetic energy (E) of a body with mass m =
0.044 kilograms and velocity v = 403.25 m/s equals 3577.43 J
Kinetic energy of each mole of the different gases
|
GAS |
kinetic energy (Heat) at 14°C |
|
Nitrogen (N2) |
3577.42 J |
|
Oxygen (O2) |
3577.39 J |
|
Argón (Ar) |
3577.40 J |
|
Carbón
Dioxide (CO2) |
3577.43 J. |
|
The
parts per million of the following gases in the atmosphere |
|
|
GAS |
parts
per million |
|
Nitrogen (N2) |
780.800 |
|
Oxygen (O2) |
209.450 |
|
Argón (Ar) |
9.340 |
|
Carbón
Dioxide (CO2) |
410 |
|
GAS |
VOLUME PPM |
Kinetic energy per Mole gas 14°C |
TOTAL(Ek) Mole Gas x Volume 14°C |
|
Nitrogen (N2) |
780.800 |
3577.42J |
2.793.249.536 J |
|
Oxygen (O2) |
209.450 |
3577.39J |
749.284.335
J |
|
Argón (Ar) |
9.340 |
3577.40J |
33.412.916
J |
|
carbón Dioxide(CO2) |
410 |
3577.43J |
1.466.746
J |
|
TOTAL |
1.000.000 |
3577,41 j |
3.577.410.000 J |
“If you can
measure what you are talking about, and if you can express it by a number, then
you may think you know something; but if you can't measure it, your knowledge
will be poor and unsatisfactory”
Lord Kelvin
Conclusión
|
GAS |
Vcm. Speed Of molecules at 14°C |
Kinetic energy per Mole gas at 14°C |
Vcm. Speed Of molecules at 15°C |
Kinetic energy per Mole gas at 15°C |
|
Nitrogen (N2) |
505.50 m/s |
3577.42 J |
506.38 m/s |
3589.89 J |
|
Oxygen (O2) |
472.85 m/s |
3577.39 J |
473.67 m/s |
3589.81 J |
|
Argón (Ar) |
423.46 m/s |
3577.40 J |
424.20 m/s |
3589.92 J |
|
carbón Dioxide(CO2) |
403.25 m/s. |
3577.43 J |
403.95 m/s. |
3589.86 J. |
|
Average |
451.26 m/s |
3577,41 J |
452.05 m/s |
3589.87J |
We can conclude
that the average kinetic energy that originates each mole of gas from the 4
main gases in the atmosphere at 15°C is 3589.87 Joules, and the molecules move
to an average of 452.05 m / s, now each mole of gas at 14°C produces a kinetic
energy of 3577.41 Joules, and molecules move with an average of 451.26 m/s,
this shows us that the heat that molecules in the atmosphere can transfer is
greater, when the temperature of the atmosphere increases, and that the
increase in the kinetic energy of molecules, is due to an increase in their
quadratic velocity. According to this data when a mole of gas molecules in the
atmosphere go from 14°C to 15°C, its ability to transfer its energy or heat
increases by 12.46Julios, which is an increase by 0.34% in heat for each degree
Celsius of temperature increase, and the average speed of molecules increases
by 1.24 m/s.
Finally it can
be concluded that when the atmosphere increases its temperature by 1 degree
centigrade, the heat on the planet increases by 0.34%.
Bibliography
1-
Intergovernmental Panel on Climate Change. Consultado el 15 de octubre de 2010.
1.1-https://www.carbonbrief.org/guest-post-why-low-end-climate-sensitivity-can-now-be-ruled-out
1.2-https://advances.sciencemag.org/content/6/26/eaba1981
A concise description of the greenhouse effect is given in the
Intergovernmental Panel on Climate Change Fourth Assessment Report, "What
is the Greenhouse Effect?" FAQ 1.3 - AR4 WGI Chapter 1: Historical
Overview of Climate Change Science, IIPCC Fourth Assessment Report, Chapter 1,
page
2- Maxwell, J.
C. (1867). "On the Dynamical Theory of Gases". Philosophical
Transactions of the Royal Society of London 157: 49
3-http://www.educaplus.org/gases/ley_charles.html
4-https://www.khanacademy.org/science/chemistry/thermodynamics-chemistry/internal-energy-sal/a/heat
5-https://www.khanacademy.org/science/chemistry/thermodynamics-chemistry/internal-energy-sal/a/heat
6-
http://hyperphysics.phy-astr.gsu.edu/hbase/Kinetic/eqpar.html
7-
https://en.wikipedia.org/wiki/Equipartition_theorem
8-https://es.wikipedia.org/wiki/Mol#cite_note-avogadro-constant-4
9-https://es.calcprofi.com/energia-cinetica-formula-calculadora.html






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